**Five year hence the age of jacob will be three times that of his son. 5 years ago jacob was seven time that of his son. What are their present ages ?**

Solution : let present age of Jacob be x years and the present age of the son be y years.

5 years hence

Age of Jacob = ( x + 5) yrs

Age of son = ( y + 5) yrs

A.T.Q. x + 5 = 3 (y + 5)

x +5 = 3y + 15

x – 3y = 10 ………..(i)

5 years ago age of Jacob= ( x -5) yrs

5 years ago age of son = ( y -5) yrs

A.T.Q. x-5 = 7 (y-5)

x -5 = 7y -35

x = 7y – 30 ………..(ii)

Put equation (ii) in (i)

7y -30 – 3y = 10

4y = 40

y = 10. Put y = 10 in (ii)

So x = 7 X 10 – 30

x = 70-30

So x = 40

Hence the present age of Jacob is 40 years and that of son is 10 yrs.

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Ncert Solutions Class 10 Maths Exercise 4.3 https://10thmathsguide.com/exercise-43-class-10-maths/

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