Five year hence the age of jacob will be three times that of his son. 5 years ago jacob was seven time that of his son. What are their present ages ?
Solution : let present age of Jacob be x years and the present age of the son be y years.
5 years hence
Age of Jacob = ( x + 5) yrs
Age of son = ( y + 5) yrs
A.T.Q. x + 5 = 3 (y + 5)
x +5 = 3y + 15
x – 3y = 10 ………..(i)
5 years ago age of Jacob= ( x -5) yrs
5 years ago age of son = ( y -5) yrs
A.T.Q. x-5 = 7 (y-5)
x -5 = 7y -35
x = 7y – 30 ………..(ii)
Put equation (ii) in (i)
7y -30 – 3y = 10
4y = 40
y = 10. Put y = 10 in (ii)
So x = 7 X 10 – 30
x = 70-30
So x = 40
Hence the present age of Jacob is 40 years and that of son is 10 yrs.
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